查找N个数组的公共元素
大约 1 分钟
#include <iostream>
#include <vector>
#include <unordered_set>
using std::cout;
using std::endl;
using std::cin;
using std::vector;
using std::unordered_set;
//因为set比数组占用的空间大,并且set把数值映射到key都要做hash计算,速度也比数组慢
//如果数组数值范围可控可以使用数组做hash
const int M = 20; //数值的范围
vector<int> getIntersection3(const vector<int>& nums1, const vector<int>& nums2) {
unordered_set<int> result_set; //给结果去重
int hashTable[M] = {0};
for(int num : nums1) {
hashTable[num] = 1;
}
for(int num : nums2) {
if(hashTable[num] == 1) {
result_set.insert(num);
}
}
return vector(result_set.begin(), result_set.end());
}
void print(const vector<int>& vec) {
for(int i : vec) {
cout << i << ' ';
}
cout << endl;
}
int main() {
vector<vector<int>> arr = { {0,1,2,3,4,5,6,7,8,9},{1,1,2,2,3,4,5,6,7,9},{1,2,3,3,4, 4,4,6,6,7},{1,2,3,4,6,7,8,9,10,10},{1,1,2,2,3,3,4,4,6,8} };
vector<int> ret = getIntersection3(arr[0],arr[1]);
for(int i = 2; i < arr.size(); ++i) {
ret = getIntersection3(arr[i], ret);
}
print(ret);
}